Integrand size = 23, antiderivative size = 190 \[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\frac {a^2 \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) \sin (c+d x) (e \sin (c+d x))^m}{d (1+m) \sqrt {\cos ^2(c+d x)}}+\frac {2 a b \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) (e \sin (c+d x))^{1+m}}{d e (1+m)}+\frac {b^2 \sqrt {\cos ^2(c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) (e \sin (c+d x))^m \tan (c+d x)}{d (1+m)} \]
[Out]
Time = 0.99 (sec) , antiderivative size = 190, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {3957, 2990, 2644, 371, 4483, 4486, 2722, 2657} \[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\frac {a^2 \sin (c+d x) \cos (c+d x) (e \sin (c+d x))^m \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m+1}{2},\frac {m+3}{2},\sin ^2(c+d x)\right )}{d (m+1) \sqrt {\cos ^2(c+d x)}}+\frac {2 a b (e \sin (c+d x))^{m+1} \operatorname {Hypergeometric2F1}\left (1,\frac {m+1}{2},\frac {m+3}{2},\sin ^2(c+d x)\right )}{d e (m+1)}+\frac {b^2 \sqrt {\cos ^2(c+d x)} \tan (c+d x) (e \sin (c+d x))^m \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {m+1}{2},\frac {m+3}{2},\sin ^2(c+d x)\right )}{d (m+1)} \]
[In]
[Out]
Rule 371
Rule 2644
Rule 2657
Rule 2722
Rule 2990
Rule 3957
Rule 4483
Rule 4486
Rubi steps \begin{align*} \text {integral}& = \int (-b-a \cos (c+d x))^2 \sec ^2(c+d x) (e \sin (c+d x))^m \, dx \\ & = (2 a b) \int \sec (c+d x) (e \sin (c+d x))^m \, dx+\int \left (b^2+a^2 \cos ^2(c+d x)\right ) \sec ^2(c+d x) (e \sin (c+d x))^m \, dx \\ & = \frac {(2 a b) \text {Subst}\left (\int \frac {x^m}{1-\frac {x^2}{e^2}} \, dx,x,e \sin (c+d x)\right )}{d e}+\left (\sin ^{-m}(c+d x) (e \sin (c+d x))^m\right ) \int \left (b^2+a^2 \cos ^2(c+d x)\right ) \sec ^2(c+d x) \sin ^m(c+d x) \, dx \\ & = \frac {2 a b \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) (e \sin (c+d x))^{1+m}}{d e (1+m)}+\left (\sin ^{-m}(c+d x) (e \sin (c+d x))^m\right ) \int \left (a^2 \sin ^m(c+d x)+b^2 \sec ^2(c+d x) \sin ^m(c+d x)\right ) \, dx \\ & = \frac {2 a b \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) (e \sin (c+d x))^{1+m}}{d e (1+m)}+\left (a^2 \sin ^{-m}(c+d x) (e \sin (c+d x))^m\right ) \int \sin ^m(c+d x) \, dx+\left (b^2 \sin ^{-m}(c+d x) (e \sin (c+d x))^m\right ) \int \sec ^2(c+d x) \sin ^m(c+d x) \, dx \\ & = \frac {a^2 \cos (c+d x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) \sin (c+d x) (e \sin (c+d x))^m}{d (1+m) \sqrt {\cos ^2(c+d x)}}+\frac {2 a b \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) (e \sin (c+d x))^{1+m}}{d e (1+m)}+\frac {b^2 \sqrt {\cos ^2(c+d x)} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) (e \sin (c+d x))^m \tan (c+d x)}{d (1+m)} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 134, normalized size of antiderivative = 0.71 \[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\frac {(e \sin (c+d x))^m \left (2 a b \operatorname {Hypergeometric2F1}\left (1,\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right ) \sin (c+d x)+\sqrt {\cos ^2(c+d x)} \left (a^2 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right )+b^2 \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {1+m}{2},\frac {3+m}{2},\sin ^2(c+d x)\right )\right ) \tan (c+d x)\right )}{d (1+m)} \]
[In]
[Out]
\[\int \left (a +b \sec \left (d x +c \right )\right )^{2} \left (e \sin \left (d x +c \right )\right )^{m}d x\]
[In]
[Out]
\[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\int { {\left (b \sec \left (d x + c\right ) + a\right )}^{2} \left (e \sin \left (d x + c\right )\right )^{m} \,d x } \]
[In]
[Out]
\[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\int \left (e \sin {\left (c + d x \right )}\right )^{m} \left (a + b \sec {\left (c + d x \right )}\right )^{2}\, dx \]
[In]
[Out]
\[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\int { {\left (b \sec \left (d x + c\right ) + a\right )}^{2} \left (e \sin \left (d x + c\right )\right )^{m} \,d x } \]
[In]
[Out]
\[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\int { {\left (b \sec \left (d x + c\right ) + a\right )}^{2} \left (e \sin \left (d x + c\right )\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int (a+b \sec (c+d x))^2 (e \sin (c+d x))^m \, dx=\int {\left (e\,\sin \left (c+d\,x\right )\right )}^m\,{\left (a+\frac {b}{\cos \left (c+d\,x\right )}\right )}^2 \,d x \]
[In]
[Out]